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Methods for solving exponential equations

Exponential equations
An equation af(x)=ag(x)a^{f(x)}=a^{g(x)} with a>0a>0, a1a\neq1 is equivalent to f(x)=g(x)f(x)=g(x) (monotonicity of the exponential in xx). If the bases differ, try to reduce to one base or take a logarithm of an admissible base (watch the domain). The form af(x)=ba^{f(x)}=b with b>0b>0 is solved as f(x)=logabf(x)=\log_a b. Sums like Aa2x+Bax+C=0A\cdot a^{2x}+B\cdot a^x+C=0 are usually turned into a quadratic: t=ax>0t=a^x>0.
After substituting t=axt=a^x, discard roots with t0t\le0
Techniques
SituationStep
The same aa on both sidesreduce to af=aga^{f}=a^{g}, then f=gf=g
4x4^x and 2x2^xwrite 4x=(22)x=22x4^x=(2^2)^x=2^{2x}
3x+3x+1=123^x+3^{x+1}=12factor out 3x3^x
Mixture of exponential and constantslg\lg / ln\ln of both sides when the sides are positive
Simplify the exponential “core” before equating exponents.
262^6
Apply exponent rules and simplify.
=64=64
The numeric equation 2x=82^x=8 is the intersection of y=2xy=2^x with the level y=8y=8: x=3x=3.
0246810-101234(0; 1)xy
y=2xy=2^x
💡Next — exponential inequalities, where the solution hinges on a>1a>1 or 0<a<10<a<1.
You distinguish equivalent steps for af=aga^{f}=a^{g} and can reduce a problem to an algebraic equation or to t=axt=a^x.