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Methods for solving exponential inequalities

Inequalities af(x)>ag(x)a^{f(x)}>a^{g(x)}
If a>1a>1, ata^t increases in tt, so af>ag  f>ga^{f}>a^{g}\ \Leftrightarrow\ f>g (on the common domain of the inequality). If 0<a<10<a<1, the exponential decreases, so af>ag  f<ga^{f}>a^{g}\ \Leftrightarrow\ f<g. If the bases differ, you usually take logarithms or match bases; with ln\ln the inequality sign is unchanged (ln\ln is increasing), but both sides must be positive.
First ensure a>0a>0, a1a\neq1, and write the domain for f,gf,g
How the sign transfers
BaseFrom af>aga^f>a^g you get
a>1a>1f>gf>g
0<a<10<a<1f<gf<g
After reducing to f(x)>g(x)f(x)>g(x), intersect with the domain on the number line.
Example “interval” style answer
Solution set on the number line-10123456x
(3;+](3\,;\,+\infty]
💡Next lesson — the formal definition of the logarithm and the basic logarithmic identity.
You transfer the inequality between afa^{f} and ff, gg according to a>1a>1 or 0<a<10<a<1.