If the second factor ends in zeros, split off the significant part and a power of ten:
24⋅300=24⋅3⋅100=72⋅100=7200
First multiply the “short” numbers without the extra zeros, then append as many zeros as you set aside (or multiply by 10, 100, 1000, and so on).
The same works if the zeros are in the first factor: 180⋅4=18⋅10⋅4=18⋅4⋅10. You may swap the order of factors (a⋅b=b⋅a) when it helps.
Strip trailing zeros, multiply the short numbers, put the zeros back
⋅10, ⋅100, … — shifting places
Check: estimate the size (how many digits in the answer)
The times table for the nonzero digit — same as before
By 10 and by “round” tens
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