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Multiplying by numbers ending in zeros

If the second factor ends in zeros, split off the significant part and a power of ten: 24300=243100=72100=720024 \cdot 300 = 24 \cdot 3 \cdot 100 = 72 \cdot 100 = 7200 First multiply the “short” numbers without the extra zeros, then append as many zeros as you set aside (or multiply by 1010, 100100, 10001000, and so on). The same works if the zeros are in the first factor: 1804=18104=18410180 \cdot 4 = 18 \cdot 10 \cdot 4 = 18 \cdot 4 \cdot 10. You may swap the order of factors (ab=baa\cdot b = b\cdot a) when it helps.
Strip trailing zeros, multiply the short numbers, put the zeros back
10\cdot 10, 100\cdot 100, … — shifting places
Check: estimate the size (how many digits in the answer)
The times table for the nonzero digit — same as before
By 10 and by “round” tens
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